If the current through a coil is doubled while keeping the number of turns constant, what happens to the magnetic strength?

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Multiple Choice

If the current through a coil is doubled while keeping the number of turns constant, what happens to the magnetic strength?

Magnetic field strength from a coil scales with the current when the number of turns and the geometry are fixed. For a long solenoid, B = μ0 N I / L (or equivalently B ∝ I for fixed N and L), so doubling the current doubles the magnetic field. In other words, with the turns unchanged, increasing current increases the field proportionally, and the field strength becomes twice as large.

Magnetic field strength from a coil scales with the current when the number of turns and the geometry are fixed. For a long solenoid, B = μ0 N I / L (or equivalently B ∝ I for fixed N and L), so doubling the current doubles the magnetic field. In other words, with the turns unchanged, increasing current increases the field proportionally, and the field strength becomes twice as large.

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